57y^2+13y-45=0

Solution for 57y^2+13y-45=0 equation:

57y^2+13y-45=0

a = 57; b = 13; c = -45;
Δ = b2-4ac
Δ = 132-4·57·(-45)
Δ = 10429
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{10429}}{2*57}=\frac{-13-\sqrt{10429}}{114}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{10429}}{2*57}=\frac{-13+\sqrt{10429}}{114}
$